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(D) The double bond equivalent $(DBE)$ or degree of unsaturation is calculated as: $DBE = 	ext{Number of rings} + 	ext{Number of double bonds} + 2 \

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(D) The double bond equivalent $(DBE)$ or degree of unsaturation is calculated as: $DBE = 	ext{Number of rings} + 	ext{Number of double bonds} + 2 	imes 	ext{Number of triple bonds}$.In the given structure:$1$. There are $3$ rings (two benzene rings and one central six-membered ring).$2$. Each benzene ring has $3$ double bonds,so $2 	imes 3 = 6$ double bonds.$3$. The $-COOH$ group contains $1$ $C=O$ double bond.$4$. The phenyl group $(-Ph)$ attached to the structure is a benzene ring,which contributes $1$ ring and $3$ double bonds.Total rings = $3$ (from the main fused system) $+ 1$ (from the phenyl group) $= 4$.Total double bonds = $6$ (from the two fused benzene rings) $+ 1$ (from the $C=O$ group) $+ 3$ (from the phenyl group) $= 10$.$DBE = 4 + 10 = 14$. Wait,let's re-evaluate the structure carefully.The structure is a phenalene derivative. The core is phenalene ($3$ rings,$10$ $\pi$ electrons). The phenyl group adds $1$ ring and $3$ double bonds. The $-COOH$ group adds $1$ double bond.Total rings = $3 + 1 = 4$.Total double bonds = $5$ (in phenalene) $+ 3$ (in phenyl) $+ 1$ (in $COOH$) $= 9$.$DBE = 4 + 9 = 13$.Thus,the correct option is $D$.

Calculate the double bond equivalent $(DBE)$ for the following compound.

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