Calculate the heat given to the gas during th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a cyclic process,the change in internal energy $\Delta U = 0$.According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$,wh

Vedclass · Accepted Answer

$31.4$

Vedclass · Answer

(C) For a cyclic process,the change in internal energy $\Delta U = 0$.According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$,which implies $\Delta Q = \Delta W$.The work done $\Delta W$ in a cyclic process is equal to the area enclosed by the $P-V$ loop.The loop is a circle with diameter along the $P$-axis as $(300 - 100) 	ext{ kPa} = 200 	ext{ kPa} = 2 	imes 10^5 	ext{ Pa}$.The radius $r_P = 100 	ext{ kPa} = 10^5 	ext{ Pa}$.The diameter along the $V$-axis is $(300 - 100) 	ext{ cc} = 200 	ext{ cc} = 200 	imes 10^{-6} 	ext{ m}^3 = 2 	imes 10^{-4} 	ext{ m}^3$.The radius $r_V = 100 	ext{ cc} = 10^{-4} 	ext{ m}^3$.The area of the ellipse (or circle in this scale) is $\pi 	imes r_P 	imes r_V$.$\Delta W = \pi 	imes (10^5 	ext{ Pa}) 	imes (10^{-4} 	ext{ m}^3) = \pi 	imes 10 	ext{ J} = 3.14 	imes 10 	ext{ J} = 31.4 	ext{ J}$.Since the process is clockwise,the work done is positive,so $\Delta Q = 31.4 	ext{ J}$.

Calculate the heat given to the gas during the cyclic process $ABA$ shown in the figure (in $J$).

Similar Questions

The $P-V$ graph of an ideal gas cycle is shown below. The adiabatic processes are described by:

The $P-V$ diagram of an ideal gas is as shown. Find the work done by the gas in the $ABCD$ process.

An ideal gas is taken from point $A$ to point $C$ on a $P-V$ diagram through two processes $AOC$ and $ABC$ as shown in the figure. Process $AOC$ is isothermal.

What is the total work done in the given $P-V$ graph?

Work done by a gas in the process shown in the figure will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module