Calculate the molar conductivity of a $0.02 \, M$ solution if its conductivity is $2.06 \times 10^{-3} \, S \, cm^{-1}$.
(N/A) The formula for molar conductivity is $\Lambda_m = \frac{\kappa \times 1000}{C}$.
Given conductivity $\kappa = 2.06 \times 10^{-3} \, S \, cm^{-1}$ and concentration $C = 0.02 \, M$.
Substituting the values: $\Lambda_m = \frac{2.06 \times 10^{-3} \times 1000}{0.02} = \frac{2.06}{0.02} = 103 \, S \, cm^2 \, mol^{-1}$.
Given conductivity $\kappa = 2.06 \times 10^{-3} \, S \, cm^{-1}$ and concentration $C = 0.02 \, M$.
Substituting the values: $\Lambda_m = \frac{2.06 \times 10^{-3} \times 1000}{0.02} = \frac{2.06}{0.02} = 103 \, S \, cm^2 \, mol^{-1}$.
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