Calculate the molarity and % W/V of 40 volum | vedclass

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(B) The relationship between volume strength and molarity $(M)$ is given by: $Volume \ strength = 11.2 	imes M$. Given volume strength = $40$. Theref

Vedclass · Accepted Answer

$3.57 \ M, 12.14\%$

Vedclass · Answer

(B) The relationship between volume strength and molarity $(M)$ is given by: $Volume \ strength = 11.2 	imes M$. Given volume strength = $40$. Therefore,$M = \frac{40}{11.2} \approx 3.57 \ M$. Now,$\% \ W/V = 	ext{Molarity} 	imes \frac{	ext{Molar mass of } H_2O_2}{10}$. Molar mass of $H_2O_2 = (2 	imes 1) + (2 	imes 16) = 34 \ g/mol$. $\% \ W/V = 3.57 	imes \frac{34}{10} = 3.57 	imes 3.4 = 12.138 \approx 12.14\%$. Thus,the molarity is $3.57 \ M$ and the $\% \ W/V$ is $12.14\%$.

Calculate the molarity and $\% \ W/V$ of $40$ volume of $H_2O_2$ solution.

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