Calculate the mean deviation about the mean for the following frequency distribution:
Class interval$0-4$$4-8$$8-12$$12-16$$16-20$
Frequency$4$$6$$8$$5$$2$

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First,find the mid-points $(x_i)$ for each class interval and calculate the mean $(\bar{x})$:
Class interval$f_i$$x_i$$f_i x_i$$|x_i - \bar{x}|$$f_i |x_i - \bar{x}|$
$0-4$$4$$2$$8$$|2 - 9.2| = 7.2$$28.8$
$4-8$$6$$6$$36$$|6 - 9.2| = 3.2$$19.2$
$8-12$$8$$10$$80$$|10 - 9.2| = 0.8$$6.4$
$12-16$$5$$14$$70$$|14 - 9.2| = 4.8$$24.0$
$16-20$$2$$18$$36$$|18 - 9.2| = 8.8$$17.6$
Total$\Sigma f_i = 25$$\Sigma f_i x_i = 230$$\Sigma f_i d_i = 96$

$\bar{x} = \frac{\Sigma f_i x_i}{\Sigma f_i} = \frac{230}{25} = 9.2$
$\text{Mean deviation} = \frac{\Sigma f_i |x_i - \bar{x}|}{\Sigma f_i} = \frac{96}{25} = 3.84$

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