For a frequency distribution,the mean deviati | vedclass

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Question

(C) The mean deviation about the mean for a frequency distribution is given by the formula $M.D.(\bar{x}) = \frac{\sum_{i=1}^{n} f_i |x_i - \bar{x}|}{

Vedclass · Accepted Answer

$M.D. = \frac{\sum f|d|}{\sum f}$

Vedclass · Answer

(C) The mean deviation about the mean for a frequency distribution is given by the formula $M.D.(\bar{x}) = \frac{\sum_{i=1}^{n} f_i |x_i - \bar{x}|}{\sum_{i=1}^{n} f_i}$.Here,$d_i = x_i - \bar{x}$ represents the deviation of the $i$-th observation from the mean $\bar{x}$.Thus,the formula can be written as $M.D. = \frac{\sum f|d|}{\sum f}$.Therefore,option $C$ is correct.

Income per day	Number of persons
$0-100$	$4$
$100-200$	$8$
$200-300$	$9$
$300-400$	$10$
$400-500$	$7$
$500-600$	$5$
$600-700$	$4$
$700-800$	$3$

For a frequency distribution,the mean deviation from the mean is computed by:

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