Calculate the mean of the following frequency | vedclass

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(D) To calculate the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)

Vedclass · Accepted Answer

$122$

Vedclass · Answer

(D) To calculate the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$,where $x_i$ is the class mark.$1$. Calculate class marks $(x_i)$: $85, 95, 105, 115, 125, 135, 145, 155, 165$.$2$. Calculate $f_i x_i$:$6 	imes 85 = 510$$18 	imes 95 = 1710$$78 	imes 105 = 8190$$80 	imes 115 = 9200$$100 	imes 125 = 12500$$72 	imes 135 = 9720$$0 	imes 145 = 0$$40 	imes 155 = 6200$$6 	imes 165 = 990$$3$. Sum of frequencies $\sum f_i = 6 + 18 + 78 + 80 + 100 + 72 + 0 + 40 + 6 = 400$.$4$. Sum of products $\sum f_i x_i = 510 + 1710 + 8190 + 9200 + 12500 + 9720 + 0 + 6200 + 990 = 49020$.$5$. Mean $\bar{x} = \frac{49020}{400} = 122.55$.

Weight (in $kg$)	$100-110$	$110-120$	$120-130$	$130-140$	$140-150$
Number of wrestlers	$4$	$14$	$21$	$8$	$3$

Calculate the mean of the following frequency distribution:

Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$

Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$
(in $.55$)

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Calculate the mean of the following frequency distribution: Class $80-90$ $90-100$ $100-110$ $110-120$ $120-130$ $130-140$ $140-150$ $150-160$ $160-170$ Frequency $6$ $18$ $78$ $80$ $100$ $72$ $0$ $40$ $6$ (in $.55$)