The formula to find the mean of an ungrouped data is ........
- A$\bar{x}=\Sigma x_{i}$
- B$\bar{x}=\frac{\Sigma x_{i}}{n}$
- C$\bar{x}=\frac{\Sigma x_{i}}{2}$
- D$\bar{x}=n \cdot \Sigma x_{i}$
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Similar Questions
Midpoint (Midvalue) of the class $15-30$ is ........
Easy
View SolutionThe marks obtained by $30$ students of Class $X$ of a certain school in a Mathematics paper consisting of $100$ marks are presented in the table below. Find the mean of the marks obtained by the students.
Marks obtained $(x_{i})$ $10, 20, 36, 40, 50, 56, 60, 70, 72, 80, 88, 92, 95$ Number of students $(f_{i})$ $1, 1, 3, 4, 3, 2, 4, 4, 1, 1, 2, 3, 1$
| Marks obtained $(x_{i})$ | $10, 20, 36, 40, 50, 56, 60, 70, 72, 80, 88, 92, 95$ |
| Number of students $(f_{i})$ | $1, 1, 3, 4, 3, 2, 4, 4, 1, 1, 2, 3, 1$ |
Easy
View SolutionThe mean of the following data is $16.$ Find the missing frequency $f.$
Class $0-4$ $4-8$ $8-12$ $12-16$ $16-20$ $20-24$ $24-28$ $28-32$ $32-36$ Frequency $6$ $8$ $17$ $23$ $16$ $15$ $f$ $4$ $3$
| Class | $0-4$ | $4-8$ | $8-12$ | $12-16$ | $16-20$ | $20-24$ | $24-28$ | $28-32$ | $32-36$ |
| Frequency | $6$ | $8$ | $17$ | $23$ | $16$ | $15$ | $f$ | $4$ | $3$ |
Difficult
View SolutionFind the mean of the following frequency distribution:
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ Frequency $2$ $10$ $40$ $25$ $13$ $10$
(in $.7$)
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ |
| Frequency | $2$ | $10$ | $40$ | $25$ | $13$ | $10$ |
Medium
View SolutionThe average age of Ina,Mina,and Dika is $x$ years. After $y$ years,what will be their average age?
Medium
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