The mean of the following data is 16. Find th | vedclass

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(A) To find the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$.First,calculate the class marks $(x_i)$ for each interval: $2, 6, 10

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$8$

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(A) To find the mean,we use the formula $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$.First,calculate the class marks $(x_i)$ for each interval: $2, 6, 10, 14, 18, 22, 26, 30, 34$.Next,calculate $f_i x_i$ for each class:$6 	imes 2 = 12$$8 	imes 6 = 48$$17 	imes 10 = 170$$23 	imes 14 = 322$$16 	imes 18 = 288$$15 	imes 22 = 330$$f 	imes 26 = 26f$$4 	imes 30 = 120$$3 	imes 34 = 102$Sum of frequencies $\sum f_i = 6+8+17+23+16+15+f+4+3 = 92+f$.Sum of $f_i x_i = 12+48+170+322+288+330+26f+120+102 = 1392+26f$.Given mean $\bar{x} = 16$,so $16 = \frac{1392+26f}{92+f}$.$16(92+f) = 1392+26f$$1472 + 16f = 1392 + 26f$$1472 - 1392 = 26f - 16f$$80 = 10f$$f = 8$.

Class	$0-4$	$4-8$	$8-12$	$12-16$	$16-20$	$20-24$	$24-28$	$28-32$	$32-36$
Frequency	$6$	$8$	$17$	$23$	$16$	$15$	$f$	$4$	$3$

Class	$15-35$	$35-55$	$55-75$	$75-95$	$95-115$
Frequency	$17$	$f_1$	$32$	$f_2$	$19$

Daily pocket allowance (in $Rs.$)	$11-13$	$13-15$	$15-17$	$17-19$	$19-21$	$21-23$	$23-25$
Number of children	$7$	$6$	$9$	$13$	$f$	$5$	$4$

The mean of the following data is $16.$ Find the missing frequency $f.$

Class $0-4$ $4-8$ $8-12$ $12-16$ $16-20$ $20-24$ $24-28$ $28-32$ $32-36$

Frequency $6$ $8$ $17$ $23$ $16$ $15$ $f$ $4$ $3$

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The mean of the following data is $16.$ Find the missing frequency $f.$ Class $0-4$ $4-8$ $8-12$ $12-16$ $16-20$ $20-24$ $24-28$ $28-32$ $32-36$ Frequency $6$ $8$ $17$ $23$ $16$ $15$ $f$ $4$ $3$