Calculate the molar mass of a solute at $300 \ K$ if $400 \ mg$ of it is dissolved in $300 \ mL$ of water to exert an osmotic pressure of $0.2 \ atm$. $(R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1})$
- A$90 \ g \ mol^{-1}$
- B$120 \ g \ mol^{-1}$
- C$164 \ g \ mol^{-1}$
- D$180 \ g \ mol^{-1}$
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