Calculate the molarity of NaOH in the solutio | vedclass

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(B) Molarity $(M)$ is defined as the number of moles of solute per litre of solution.$M = \frac{	ext{Number of moles of solute}}{	ext{Volume of solu

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$0.4$

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(B) Molarity $(M)$ is defined as the number of moles of solute per litre of solution.$M = \frac{	ext{Number of moles of solute}}{	ext{Volume of solution in litres}}$First,calculate the number of moles of $NaOH$:$	ext{Moles of } NaOH = \frac{	ext{Mass}}{	ext{Molar mass}} = \frac{4 \,g}{40 \,g \,mol^{-1}} = 0.1 \,mol$Next,convert the volume of the solution to litres:$250 \,mL = 0.250 \,L$Now,calculate the molarity:$M = \frac{0.1 \,mol}{0.250 \,L} = 0.4 \,mol \,L^{-1} = 0.4 \,M$

Calculate the molarity of $NaOH$ in the solution prepared by dissolving $4 \,g$ of it in enough water to form $250 \,mL$ of the solution. (in $,M$)

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