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(A) $1$. At $STP$, $1 	ext{ mole}$ of any gas occupies a volume of $22.4 	ext{ dm}^3$.$2$. The number of moles $(n)$ in $2.24 	ext{ dm}^3$ of $CO_2

Vedclass · Accepted Answer

$6.022 	imes 10^{22}$

Vedclass · Answer

(A) $1$. At $STP$, $1 	ext{ mole}$ of any gas occupies a volume of $22.4 	ext{ dm}^3$.$2$. The number of moles $(n)$ in $2.24 	ext{ dm}^3$ of $CO_2$ is calculated as: $n = \frac{	ext{Given Volume}}{	ext{Molar Volume}} = \frac{2.24 	ext{ dm}^3}{22.4 	ext{ dm}^3/	ext{mol}} = 0.1 	ext{ mol}$.$3$. The number of molecules is given by: $	ext{Number of molecules} = n 	imes N_A$, where $N_A$ is Avogadro's number $(6.022 	imes 10^{23} 	ext{ molecules/mol})$.$4$. Therefore, $	ext{Number of molecules} = 0.1 	imes 6.022 	imes 10^{23} = 6.022 	imes 10^{22}$ molecules.

Calculate the number of molecules present in $2.24 \text{ dm}^3$ of carbon dioxide $(CO_2)$ at $STP$.

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