Calculate the volume of H_2 gas kept at STP i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Molar mass of $H_3PO_4 = (3 	imes 1) + 31 + (4 	imes 16) = 98 \ g/mol$.Given mass of $H_3PO_4 = 98 \ g$,so moles of $H_3PO_4 = 98/98 = 1 \ mol$.

Vedclass · Accepted Answer

$33.6$

Vedclass · Answer

(A) Molar mass of $H_3PO_4 = (3 	imes 1) + 31 + (4 	imes 16) = 98 \ g/mol$.Given mass of $H_3PO_4 = 98 \ g$,so moles of $H_3PO_4 = 98/98 = 1 \ mol$.Each molecule of $H_3PO_4$ contains $3$ atoms of $H$.Therefore,total moles of $H$ atoms $= 1 \ mol 	imes 3 = 3 \ mol$ of $H$ atoms.Let the volume of $H_2$ gas at $STP$ be $V \ L$.Number of moles of $H_2$ gas $= V/22.4 \ mol$.Since each molecule of $H_2$ contains $2$ atoms of $H$,moles of $H$ atoms in $H_2$ gas $= 2 	imes (V/22.4) = V/11.2 \ mol$.Equating the moles of $H$ atoms: $V/11.2 = 3$.$V = 3 	imes 11.2 = 33.6 \ L$.

Calculate the volume of $H_2$ gas kept at $STP$ if it contains as many $H$ atoms as in $98 \ g$ of $H_3PO_4$. (Atomic mass of $P = 31 \ u$) (in $L$)

Similar Questions

$100 \ mL$ of $0.1 \ N$ hypo solution is decolourised by the iodine liberated from the addition of $x \ g$ of crystalline copper sulphate to an excess of $KI$. The value of $x$ is ............. $g$ (molecular weight of $CuSO_4 \cdot 5H_2O$ is $250$).

The amount of carbon dioxide evolved upon complete combustion of $116 \ g$ of $n$-butane is
(Given : atomic mass in amu $H = 1, C = 12$ and $O = 16$) (in $g$)

The normality of $0.3 \ M$ phosphorous acid $(H_3PO_3)$ is

If one wants to make methanol out of synthesis gas,what should be the ratio of the gaseous components in the synthesis gas?

$120 \ g$ of urea are present in $5 \ L$ of solution. The active mass of urea is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module