Can the number $6^{n}$,where $n$ is a natural number,end with the digit $5$? Give reasons.

(NO) No,the number $6^{n}$ cannot end with the digit $5$.
For any number to end with the digit $5$,its prime factorization must contain the prime factor $5$.
The prime factorization of $6^{n}$ is given by $6^{n} = (2 \times 3)^{n} = 2^{n} \times 3^{n}$.
Since the only prime factors of $6^{n}$ are $2$ and $3$,and $5$ is not a prime factor,$6^{n}$ can never end with the digit $5$ for any natural number $n$.