Capacity of a capacitor is 48 mu F. When it i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The energy stored in a capacitor is given by $U = \frac{q^2}{2C}$.Given: $C = 48 \mu F = 48 	imes 10^{-6} \ F$,$q_1 = 0.1 \ C$,$q_2 = 0.5 \ C$.Th

Vedclass · Accepted Answer

$2500 \ J$

Vedclass · Answer

(A) The energy stored in a capacitor is given by $U = \frac{q^2}{2C}$.Given: $C = 48 \mu F = 48 	imes 10^{-6} \ F$,$q_1 = 0.1 \ C$,$q_2 = 0.5 \ C$.The change in energy $\Delta U$ is given by:$\Delta U = U_2 - U_1 = \frac{q_2^2}{2C} - \frac{q_1^2}{2C} = \frac{1}{2C} (q_2^2 - q_1^2)$Substituting the values:$\Delta U = \frac{1}{2 	imes 48 	imes 10^{-6}} ((0.5)^2 - (0.1)^2)$$\Delta U = \frac{1}{96 	imes 10^{-6}} (0.25 - 0.01)$$\Delta U = \frac{0.24}{96 	imes 10^{-6}}$$\Delta U = \frac{0.24 	imes 10^6}{96} = \frac{240000}{96} = 2500 \ J$.

Capacity of a capacitor is $48 \mu F$. When it is charged from $0.1 C$ to $0.5 C$,the change in the energy stored is:

Similar Questions

In steady state,the energy stored in the capacitor as shown in the figure is ..... $nJ$.

Two capacitors,one of capacity $C$ and other of capacity $C/2$ are connected to a $V$ volt battery,as shown in the figure. The work done in charging fully both the capacitors is

An air-filled parallel plate capacitor has a uniform electric field $E$ in the space between the plates. If the distance between the plates is $d$ and the area of each plate is $A$,the energy stored in the capacitor is ($\epsilon_{0} =$ permittivity of free space).

$A$ $12\,pF$ capacitor is connected to a $50\,V$ battery. How much electrostatic energy is stored in the capacitor?

$A$ $5.0 \mu F$ capacitor is charged to a potential difference of $800 V$ and discharged through a conductor. The energy (in $J$) given to the conductor during the discharge is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module