Characteristic $X$-rays:

The minimum wavelength of the $X$-rays produced at an accelerating potential $V$ is $\lambda$. If the accelerating potential is changed to $2V$, then the minimum wavelength would become:

The difference between soft and hard $X-$rays is due to their:

The $X$-ray wavelength of the $L_{\alpha}$ line of platinum $(Z=78)$ is $1.30 \ \mathring{A}$. The $X$-ray wavelength of the $L_{\alpha}$ line of Molybdenum $(Z=42)$ is ............. $\mathring{A}$.

The wavelength of the $K_\alpha$ line for an element of atomic number $Z_1 = 29$ is $\lambda$. What is the wavelength of the $K_\alpha$ line for an element of atomic number $Z_2 = 15$? (Take Moseley's constant $b = 1$ for both elements.)

The energy of $X$-rays with a wavelength of $1.65 \, \mathring{A}$ is ............. $keV$ (Given: $h = 6.6 \times 10^{-34} \, J \cdot s$,$c = 3 \times 10^{8} \, m/s$,$1 \, eV = 1.6 \times 10^{-19} \, J$). (in $.5$)