(A) Expand both sides of the equation:$(2x - 1)(x - 3) = 2x^2 - 6x - x + 3 = 2x^2 - 7x + 3$$(x + 5)(x - 1) = x^2 - x + 5x - 5 = x^2 + 4x - 5$Equating

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Yes,it is a quadratic equation.

(A) Expand both sides of the equation:$(2x - 1)(x - 3) = 2x^2 - 6x - x + 3 = 2x^2 - 7x + 3$$(x + 5)(x - 1) = x^2 - x + 5x - 5 = x^2 + 4x - 5$Equating both sides:$2x^2 - 7x + 3 = x^2 + 4x - 5$Rearranging the terms to one side:$2x^2 - x^2 - 7x - 4x + 3 + 5 = 0$$x^2 - 11x + 8 = 0$Since this equation is in the form $ax^2 + bx + c = 0$ where $a \neq 0$,it is a quadratic equation.

Class 10 Mathematics Quadratic Equations Quadratic Equations

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Check whether the following is a quadratic equation:
$(2x - 1)(x - 3) = (x + 5)(x - 1)$

A
Yes,it is a quadratic equation.
B
No,it is not a quadratic equation.
C
It is a linear equation.
D
It is a cubic equation.

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Check whether the following is a quadratic equation:$(2x - 1)(x - 3) = (x + 5)(x - 1)$

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Verify whether the given value of $x$ is a solution of the quadratic equation or not: $x + \frac{1}{x} = 3 \frac{1}{3}$; $x = \frac{1}{3}$.

Examine whether the following equation is quadratic or not: $\sqrt{2} x^{2}-5 \sqrt{3} x+6=0$

$A$ prayer hall has a carpet area of $300 \ m^2$ with its length one metre more than twice its breadth. Find the dimensions of the prayer hall.

Find the roots of the following quadratic equation by the method of completing the square: $3 y^{2}+7 y-20=0$

Find the roots of the following quadratic equation by the method of completing the square: $4x^{2} + 20x + 23 = 0$.

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Check whether the following is a quadratic equation:
$(2x - 1)(x - 3) = (x + 5)(x - 1)$