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(B) To solve this,we observe the pattern of the series: $a \_ \_ b a \_ \_ \_ b \_ \_ \_ \_ b \_ \_ \_ \_ a \_ \_ \_ \_ b$.By analyzing the gaps,we ca

Vedclass · Accepted Answer

$abbab$

Vedclass · Answer

(B) To solve this,we observe the pattern of the series: $a \_ \_ b a \_ \_ \_ b \_ \_ \_ \_ b \_ \_ \_ \_ a \_ \_ \_ \_ b$.By analyzing the gaps,we can identify a repeating unit.The series follows the pattern: $abb / abb / abb / abb$.If we fill the blanks with $abbab$,the sequence becomes $a(b)b / a(b)b / a(b)b / a(b)b$,which completes the series logically.

Choose the correct alternative to complete the series:
$a \_ \_ b a \_ \_ \_ b \_ \_ \_ \_ b \_ \_ \_ \_ a \_ \_ \_ \_ b$

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Choose the correct alternative to complete the series:$a \_ \_ b a \_ \_ \_ b \_ \_ \_ \_ b \_ \_ \_ \_ a \_ \_ \_ \_ b$