Compare x and y bond angles in the following | vedclass

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(A) In $SO_2Cl_2$,the central sulfur atom is $sp^3$ hybridized.According to $VSEPR$ theory,the repulsion between bond pairs follows the order: $double

Vedclass · Accepted Answer

$x > y$

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(A) In $SO_2Cl_2$,the central sulfur atom is $sp^3$ hybridized.According to $VSEPR$ theory,the repulsion between bond pairs follows the order: $double-double > double-single > single-single$.Here,$x$ is the angle between two $S=O$ double bonds,and $y$ is the angle between two $S-Cl$ single bonds.Since the repulsion between the two $S=O$ double bonds is greater than the repulsion between the two $S-Cl$ single bonds,the bond angle $x$ will be greater than the bond angle $y$ $(x > y)$.

Compare $x$ and $y$ bond angles in the following molecule:

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