The complex compound [Co(SCN)_2(NH_3)_4]Cl do | vedclass

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(D) $1$. The complex $[Co(SCN)_2(NH_3)_4]Cl$ contains an ambidentate ligand $SCN^-$,which allows for linkage isomerism.$2$. It can exhibit ionisation

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Optical isomerism

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(D) $1$. The complex $[Co(SCN)_2(NH_3)_4]Cl$ contains an ambidentate ligand $SCN^-$,which allows for linkage isomerism.$2$. It can exhibit ionisation isomerism because the $Cl^-$ ion can exchange positions with the $SCN^-$ ligand.$3$. It exhibits geometrical isomerism due to the presence of two $SCN^-$ ligands in either $cis$ or $trans$ configurations.$4$. For optical isomerism in octahedral complexes of the type $[M(A)_4(B)_2]$,the complex must be in the $cis$ form. However,the $cis$ form of $[Co(SCN)_2(NH_3)_4]^+$ has a plane of symmetry,making it achiral. Therefore,it does not exhibit optical isomerism.

The complex compound $[Co(SCN)_2(NH_3)_4]Cl$ does not exhibit which of the following types of isomerism?

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