Complex compound(s) having an even number of | vedclass

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(B) The number of stereoisomers for each complex is calculated as follows:$1$. For $[M(AA)_2b_2]^{n \pm}$: This complex has $3$ stereoisomers (cis-iso

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$[Ma_3b_3]^{n \pm}$

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(B) The number of stereoisomers for each complex is calculated as follows:$1$. For $[M(AA)_2b_2]^{n \pm}$: This complex has $3$ stereoisomers (cis-isomer which is optically active,and trans-isomer which is optically inactive).$2$. For $[Ma_3b_3]^{n \pm}$: This complex has $2$ stereoisomers (facial and meridional isomers).$3$. For $[Ma_3bcd]^{n \pm}$: This complex has $5$ stereoisomers.$4$. For $[Ma_2bcde]^{n \pm}$: This complex has $5$ stereoisomers.Among the given options,only $[Ma_3b_3]^{n \pm}$ has an even number of stereoisomers $(2)$.

Complex compound$(s)$ having an even number of space (stereo) isomers is/are :
(where $AA^{-}$ is a symmetrical bidentate ligand and $a, b, c, d, e$ are monodentate ligands)

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Complex compound$(s)$ having an even number of space (stereo) isomers is/are :(where $AA^{-}$ is a symmetrical bidentate ligand and $a, b, c, d, e$ are monodentate ligands)