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(A) The time constant of an $RC$ circuit is given by $	au = R_{eq}C$.In the given circuit, the two diodes are connected in anti-parallel. For any giv

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$2.2$

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(A) The time constant of an $RC$ circuit is given by $	au = R_{eq}C$.In the given circuit, the two diodes are connected in anti-parallel. For any given polarity of the source voltage, one diode will be forward-biased and the other will be reverse-biased.The forward-biased diode acts as a resistor of $10 \Omega$, while the reverse-biased diode acts as an open circuit (infinite resistance).Therefore, the equivalent resistance of the diode combination is $10 \Omega$.The total resistance of the circuit is $R_{total} = R + R_{diode} = 100 \Omega + 10 \Omega = 110 \Omega$.The capacitance is $C = 20 \mu	ext{F} = 20 	imes 10^{-6} 	ext{ F}$.Thus, the time constant $	au = R_{total} 	imes C = 110 \Omega 	imes 20 	imes 10^{-6} 	ext{ F} = 2200 	imes 10^{-6} 	ext{ s} = 2.2 	imes 10^{-3} 	ext{ s}$.Comparing this with $\alpha 	imes 10^{-3} 	ext{ s}$, we get $\alpha = 2.2$.

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