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(D) According to Poiseuille's law, the volume flow rate $Q$ is given by:$Q = \frac{\pi \Delta P r^4}{8 L \eta}$where $r$ is the radius, $\eta$ is the

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(D) According to Poiseuille's law, the volume flow rate $Q$ is given by:$Q = \frac{\pi \Delta P r^4}{8 L \eta}$where $r$ is the radius, $\eta$ is the viscosity, and $\Delta P$ is the pressure difference.Since the flow rate $Q$ does not depend on the density of blood, the change in density does not affect the flow rate.Taking the logarithmic differentiation of the formula:$\frac{\Delta Q}{Q} = 4 \frac{\Delta r}{r} - \frac{\Delta \eta}{\eta}$Given that the radius $r$ increases by $1 \%$ $(\frac{\Delta r}{r} = 0.01)$ and the viscosity $\eta$ increases by $1 \%$ $(\frac{\Delta \eta}{\eta} = 0.01)$:$\frac{\Delta Q}{Q} = 4(0.01) - 0.01 = 0.04 - 0.01 = 0.03$Therefore, the percentage change in the flow rate is $0.03 	imes 100 = 3 \%$.

Consider an increase of $1 \%$ in each of the radius of the artery, the viscosity of blood, and the density of blood, respectively. The percentage change in the flow rate of blood in the artery is (in $\%$)

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