Consider the following compounds:I. H_3X-NCSI | vedclass

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(C) The compounds involve back-bonding between the lone pair of the central atom ($N$ or $O$) and the vacant $d$-orbitals of the adjacent atom (if it

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If $X$ is carbon and $Y$ is silicon,then compound $I$ is more basic than compound $II$.

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(C) The compounds involve back-bonding between the lone pair of the central atom ($N$ or $O$) and the vacant $d$-orbitals of the adjacent atom (if it is Si).For $H_3C-NCS$,the $N$ atom is $sp^2$ hybridized with a lone pair,making it bent $(142^\circ)$.For $H_3Si-NCS$,the lone pair on $N$ participates in $p_{\pi}-d_{\pi}$ back-bonding with the vacant $d$-orbital of $Si$,making the $Si-N-C$ bond linear $(180^\circ)$.Similarly,for $(H_3C)_2O$,the $O$ atom is $sp^3$ hybridized,making it bent $(110^\circ)$.For $(H_3Si)_2O$,the lone pair on $O$ participates in $p_{\pi}-d_{\pi}$ back-bonding with $Si$,increasing the $Si-O-Si$ bond angle to $140^\circ$.Option $C$ is incorrect because $H_3Si-NCS$ is less basic than $H_3C-NCS$ due to the involvement of the lone pair on $N$ in back-bonding with $Si$,making it less available for donation.

Consider the following compounds:
$I. H_3X-NCS$
$II. H_3Y-NCS$
$III. (H_3X)_2O$
$IV. (H_3Y)_2O$
The incorrect statement regarding the given compounds is:

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Consider the following compounds:$I. H_3X-NCS$$II. H_3Y-NCS$$III. (H_3X)_2O$$IV. (H_3Y)_2O$The incorrect statement regarding the given compounds is: