Consider sunlight incident on a slit of width | vedclass

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(C) The width of the slit is $a = 10^4 \ \mathring{A} = 1000 \ nm$. The wavelength of visible light ranges from approximately $400 \ nm$ to $700 \ nm$

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a bright slit white at centre diffusing to regions of different colours

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(C) The width of the slit is $a = 10^4 \ \mathring{A} = 1000 \ nm$. The wavelength of visible light ranges from approximately $400 \ nm$ to $700 \ nm$. Since the slit width is comparable to the wavelength of light, diffraction occurs.In single-slit diffraction, the central maximum is formed at the center for all wavelengths. Since sunlight consists of all colors (white light), all colors overlap at the central maximum, making the center appear white.As we move away from the center, the position of the minima and secondary maxima depends on the wavelength $(\sin 	heta = n\lambda / a)$. Different colors have different wavelengths, so they will diffract by different amounts, leading to the dispersion of colors at the edges of the central bright patch.

Consider sunlight incident on a slit of width $10^4 \ \mathring{A}$. The image seen through the slit shall

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Explain diffraction by a single slit.

$A$ single slit of width $0.1\, mm$ is illuminated by a parallel beam of light of wavelength $6000\, \mathring{A}$ and diffraction bands are observed on a screen $0.5\, m$ from the slit. The distance of the third dark band from the central bright band is ........ $mm$.

In the case of Fraunhofer diffraction at a single slit,which of the following statements correctly describes the diffraction pattern on the screen?

In the diffraction pattern, the first maximum is at $30^{\circ}$, when a monochromatic light of wavelength $\lambda$ is incident on a slit of width $a$. For the same wavelength, if the slit width is changed, so that the first maximum is at $45^{\circ}$, by how much is the slit width changed?

Diffraction is more easily noticeable for sound waves than for light waves because sound waves

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