Consider the reaction shown below. Compound B | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: The reaction of $p$-aminobenzenesulfonic acid (sulfanilic acid) with $NaNO_2$ and $HCl$ at $273-278 \ K$ results in the formation of $p$

Vedclass · Accepted Answer

$HO_3S-C_6H_4-N=N-C_6H_4-N(CH_3)_2$

Vedclass · Answer

(A) Step $1$: The reaction of $p$-aminobenzenesulfonic acid (sulfanilic acid) with $NaNO_2$ and $HCl$ at $273-278 \ K$ results in the formation of $p$-benzenediazonium sulfonate (Compound $A$).
Step $2$: Compound $A$ undergoes an electrophilic aromatic substitution (coupling reaction) with $N,N$-dimethylaniline at $273 \ K$.
Step $3$: The diazonium group $-N_2^+$ acts as an electrophile and attacks the para-position of $N,N$-dimethylaniline, which is activated by the electron-donating $-N(CH_3)_2$ group.
Step $4$: The final product $B$ is $4-(dimethylamino)azobenzene-4'-sulfonic acid$, represented as $HO_3S-C_6H_4-N=N-C_6H_4-N(CH_3)_2$.

Consider the reaction shown below. Compound $B$ is:

Similar Questions

Ethyl amine on acetylation gives

Which of the following compounds reacts with acetone to form a product containing the $>C = N -$ group?

The above $(C-N)$ coupling reaction takes place at

An organic compound $[A]$ $(C_4H_{11}N)$ shows optical activity and gives $N_2$ gas on treatment with $HNO_2$. The compound $[A]$ reacts with $PhSO_2Cl$ producing a compound which is soluble in $KOH$. The structure of $A$ is:

Which among the following has the highest basic strength?

Vedclass Test Series

Exam Paper Generator

Online Exam Module