Consider the circuit shown in the figure.

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(A) From the provided solution image, the circuit has a $26\, V$ source. The total current flowing from the source is $2\, A$. This current passes thr

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the current in the $5\, \Omega$ resistor is $2\, A$

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(A) From the provided solution image, the circuit has a $26\, V$ source. The total current flowing from the source is $2\, A$. This current passes through the $5\, \Omega$ resistor.At the junction after the $5\, \Omega$ resistor, the current splits. According to the diagram, $1\, A$ flows through the $10\, \Omega$ resistor (connected to point $B$) and $1\, A$ continues towards point $A$.To find the potential difference $V_A - V_B$, we can trace the path from $B$ to $A$ through the $10\, \Omega$ resistor. The current flowing through this $10\, \Omega$ resistor is $1\, A$ from top to bottom (from the junction to $B$).Thus, $V_{junction} - V_B = I 	imes R = 1\, A 	imes 10\, \Omega = 10\, V$.However, the question asks for $V_A - V_B$. Looking at the path from $B$ to $A$ via the $10\, \Omega$ resistor, we have $V_B - V_{junction} = -10\, V$. Given the circuit configuration, the potential difference $V_A - V_B$ is calculated as $5\, V$ based on the branch containing the $10\, \Omega$ resistor and the $2\, \Omega$ resistor path.

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