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(D) Let the initial pressure of $A$ be $P_0$. The reaction is $2A(g) \rightarrow 4B(g) + C(g)$.At $t = 30$ min, let the decrease in pressure of $A$ be

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$20$

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(D) Let the initial pressure of $A$ be $P_0$. The reaction is $2A(g) \rightarrow 4B(g) + C(g)$.At $t = 30$ min, let the decrease in pressure of $A$ be $2x$. Then the pressures are: $P_A = P_0 - 2x$, $P_B = 4x$, $P_C = x$.The total pressure $P_t = (P_0 - 2x) + 4x + x = P_0 + 3x = 300$ mm Hg.At $t = \infty$, the reaction is complete, so $P_A = 0$, which means $P_0 - 2x = 0 \Rightarrow P_0 = 2x$ or $x = P_0/2$.The total pressure at $t = \infty$ is $P_\infty = P_0 + 3(P_0/2) = 2.5 P_0 = 600$ mm Hg.Solving for $P_0$: $P_0 = 600 / 2.5 = 240$ mm Hg.Substitute $P_0$ into the equation for $t = 30$ min: $240 + 3x = 300$.$3x = 60 \Rightarrow x = 20$ mm Hg.The pressure of $C(g)$ at $30$ minutes is $x = 20$ mm Hg.

Time (min)	Total pressure (mm Hg)
$30$	$300$
$\infty$	$600$

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