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(C) Element $P$ belongs to Group $15$ (Nitrogen family),so its valency is $3$ (it gains $3$ electrons to complete its octet).Element $Q$ belongs to Gr

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$P_2Q_3$

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(C) Element $P$ belongs to Group $15$ (Nitrogen family),so its valency is $3$ (it gains $3$ electrons to complete its octet).Element $Q$ belongs to Group $2$ (Alkaline earth metals),so its valency is $2$ (it loses $2$ electrons to achieve noble gas configuration).To form a neutral compound,the total positive charge must equal the total negative charge.Using the criss-cross method: $Q^{2+}$ and $P^{3-}$ combine to form $Q_3P_2$.However,based on standard chemical nomenclature where the metal (cation) is written first,the formula is $Q_3P_2$. Given the options provided,the ratio of $P$ to $Q$ is $2:3$,which corresponds to $P_2Q_3$.

Consider the following information about elements $P$ and $Q$:

Element Information

$P$ Period number: $2$,Group number: $15$

$Q$ Period number: $3$,Group number: $2$

Then,the formula of the compound formed by elements $P$ and $Q$ is:

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Element	Information
$P$	Period number: $2$,Group number: $15$
$Q$	Period number: $3$,Group number: $2$

Consider the following information about elements $P$ and $Q$: Element Information $P$ Period number: $2$,Group number: $15$ $Q$ Period number: $3$,Group number: $2$ Then,the formula of the compound formed by elements $P$ and $Q$ is: