(B) To find the oxidation state of phosphorus $(P)$ in $H_3PO_4$,let its oxidation state be $x$. The oxidation states of $H$ and $O$ are $+1$ and $-2$

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(B) To find the oxidation state of phosphorus $(P)$ in $H_3PO_4$,let its oxidation state be $x$. The oxidation states of $H$ and $O$ are $+1$ and $-2$ respectively. The sum of oxidation states in a neutral molecule is $0$. $3(+1) + x + 4(-2) = 0$ $3 + x - 8 = 0$ $x - 5 = 0$ $x = +5$. Thus,the oxidation state of phosphorus is $5$.

Class 11 Chemistry Classification of Elements and Periodicity in Properties Valency and oxidation state

Easy

The valency (oxidation state) of phosphorus in $H_3PO_4$ is

A
$2$
B
$5$
C
$4$
D
$1$

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Classification of Elements and Periodicity in Properties

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Valency and oxidation state

An element $(A)$ occurs in the short period having electronic configuration $ns^2 np^1$. The formula of its oxide will be

Medium

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If the valency of $A$ is $3$ and $B$ is $2$,then the formula of the compound formed is:

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$A$ compound contains three elements $A$,$B$ and $C$. If the oxidation states are $A = +2$,$B = +5$ and $C = -2$,the possible formula of the compound is

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Identify the element which can have the highest oxidation number among the given options.

MediumAIIMS 1996

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The valency (oxidation state) of phosphorus in $H_3PO_4$ is

Similar Questions

An element $(A)$ occurs in the short period having electronic configuration $ns^2 np^1$. The formula of its oxide will be

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