A compound contains three elements A,B and C. | vedclass

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(B) To find the formula,we need to balance the total positive and negative charges.Let the formula be $A_x(BC_y)_z$.The oxidation state of $A$ is $+2$

Vedclass · Accepted Answer

$A_3(BC_4)_2$

Vedclass · Answer

(B) To find the formula,we need to balance the total positive and negative charges.Let the formula be $A_x(BC_y)_z$.The oxidation state of $A$ is $+2$.The oxidation state of the polyatomic group $(BC_y)$ is calculated as $B + y 	imes C = +5 + y(-2) = 5 - 2y$.For the compound to be neutral,the total charge must be zero: $x(+2) + z(5 - 2y) = 0$.Testing option $B$: $A_3(BC_4)_2$.Here,$x=3$,$y=4$,$z=2$.Charge of $A = 3 	imes (+2) = +6$.Charge of $(BC_4) = +5 + 4(-2) = 5 - 8 = -3$.Total charge = $3(+2) + 2(-3) = +6 - 6 = 0$.Thus,the formula is $A_3(BC_4)_2$.

$A$ compound contains three elements $A$,$B$ and $C$. If the oxidation states are $A = +2$,$B = +5$ and $C = -2$,the possible formula of the compound is

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