Consider the following reactions:X(aq.) xrigh | vedclass

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(B) The reaction of $Cu^{2+}$ ions with potassium ferrocyanide $(K_4[Fe(CN)_6])$ produces a chocolate brown precipitate of copper$(II)$ hexacyanoferra

Vedclass · Accepted Answer

$CuCl_2$

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(B) The reaction of $Cu^{2+}$ ions with potassium ferrocyanide $(K_4[Fe(CN)_6])$ produces a chocolate brown precipitate of copper$(II)$ hexacyanoferrate$(II)$,$Cu_2[Fe(CN)_6]$.The reaction is: $2CuCl_2(aq.) + K_4[Fe(CN)_6](aq.) \rightarrow Cu_2[Fe(CN)_6](s) + 4KCl(aq.)$The reaction of $Cl^-$ ions with silver nitrate $(AgNO_3)$ produces a white precipitate of silver chloride $(AgCl)$,which is insoluble in dilute $HNO_3$.The reaction is: $CuCl_2(aq.) + 2AgNO_3(aq.) \rightarrow 2AgCl(s) + Cu(NO_3)_2(aq.)$Therefore,$X$ is $CuCl_2$.

$LIST$-$I$ (Precipitating reagent and conditions)	$LIST$-$II$ (Cation)
$A$. $NH_4Cl + NH_4OH$	$I$. $Mn^{2+}$
$B$. $NH_4OH + (NH_4)_2CO_3$	$II$. $Pb^{2+}$
$C$. $NH_4OH + NH_4Cl + H_2S$ gas	$III$. $Al^{3+}$
$D$. Dilute $HCl$	$IV$. $Sr^{2+}$

Column-$I$	Column-$II$
$(i)$ Blood like red colour	$(a)$ $Fe_4[Fe(CN)_6]_3$
$(ii)$ Sodium nitroprusside	$(b)$ $(NH_4)_2MoO_4$
$(iii)$ Ammonium molybdate	$(c)$ $[Fe(SCN)]^{2+}$
$(iv)$ Ferri-ferro cyanide	$(d)$ $Na_2[Fe(CN)_5NO]$

Consider the following reactions:
$X(aq.) \xrightarrow{K_4[Fe(CN)_6]}$ Chocolate brown ppt.
$X(aq.) \xrightarrow{AgNO_3}$ White ppt. (insoluble in dil. $HNO_3$)
Then $X$ will be:

Similar Questions

In the group $III$ radicals,in place of $NH_4Cl$,which of the following can be used?

Which of the following sulphides is yellow in colour?

Match column-$I$ and column-$II$ with correct relation:

Column-$I$ Column-$II$

$(i)$ Blood like red colour $(a)$ $Fe_4[Fe(CN)_6]_3$

$(ii)$ Sodium nitroprusside $(b)$ $(NH_4)_2MoO_4$

$(iii)$ Ammonium molybdate $(c)$ $[Fe(SCN)]^{2+}$

$(iv)$ Ferri-ferro cyanide $(d)$ $Na_2[Fe(CN)_5NO]$

Among $PbS$,$CuS$,$HgS$,$MnS$,$Ag_2S$,$NiS$,$CoS$,$Bi_2S_3$,and $SnS_2$,the total number of black coloured sulphides is

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Consider the following reactions:$X(aq.) \xrightarrow{K_4[Fe(CN)_6]}$ Chocolate brown ppt.$X(aq.) \xrightarrow{AgNO_3}$ White ppt. (insoluble in dil. $HNO_3$)Then $X$ will be: