Match column-$I$ and column-$II$ with correct relation:
Column-$I$ Column-$II$ $(i)$ Blood like red colour $(a)$ $Fe_4[Fe(CN)_6]_3$ $(ii)$ Sodium nitroprusside $(b)$ $(NH_4)_2MoO_4$ $(iii)$ Ammonium molybdate $(c)$ $[Fe(SCN)]^{2+}$ $(iv)$ Ferri-ferro cyanide $(d)$ $Na_2[Fe(CN)_5NO]$
| Column-$I$ | Column-$II$ |
|---|---|
| $(i)$ Blood like red colour | $(a)$ $Fe_4[Fe(CN)_6]_3$ |
| $(ii)$ Sodium nitroprusside | $(b)$ $(NH_4)_2MoO_4$ |
| $(iii)$ Ammonium molybdate | $(c)$ $[Fe(SCN)]^{2+}$ |
| $(iv)$ Ferri-ferro cyanide | $(d)$ $Na_2[Fe(CN)_5NO]$ |
(A) The correct matches are:
$(i)$ Blood like red colour is due to the formation of the complex $[Fe(SCN)]^{2+}$,which corresponds to $(c)$.
$(ii)$ Sodium nitroprusside is the chemical compound $Na_2[Fe(CN)_5NO]$,which corresponds to $(d)$.
$(iii)$ Ammonium molybdate is $(NH_4)_2MoO_4$,which corresponds to $(b)$.
$(iv)$ Ferri-ferro cyanide is $Fe_4[Fe(CN)_6]_3$,which corresponds to $(a)$.
Therefore,the correct matching is $(i-c), (ii-d), (iii-b), (iv-a)$.
$(i)$ Blood like red colour is due to the formation of the complex $[Fe(SCN)]^{2+}$,which corresponds to $(c)$.
$(ii)$ Sodium nitroprusside is the chemical compound $Na_2[Fe(CN)_5NO]$,which corresponds to $(d)$.
$(iii)$ Ammonium molybdate is $(NH_4)_2MoO_4$,which corresponds to $(b)$.
$(iv)$ Ferri-ferro cyanide is $Fe_4[Fe(CN)_6]_3$,which corresponds to $(a)$.
Therefore,the correct matching is $(i-c), (ii-d), (iii-b), (iv-a)$.
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Match List-$I$ with List-$II$:
List-$I$ (Ion) List-$II$ (Group Number in Cation Analysis) $A. Co^{2+}$ $I. Group-I$ $B. Mg^{2+}$ $II. Group-III$ $C. Pb^{2+}$ $III. Group-IV$ $D. Al^{3+}$ $IV. Group-VI$
Choose the correct answer from the options given below:
| List-$I$ (Ion) | List-$II$ (Group Number in Cation Analysis) |
| $A. Co^{2+}$ | $I. Group-I$ |
| $B. Mg^{2+}$ | $II. Group-III$ |
| $C. Pb^{2+}$ | $III. Group-IV$ |
| $D. Al^{3+}$ | $IV. Group-VI$ |
Choose the correct answer from the options given below:
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