Consider the following sequence of reactions:
$PhCOOH$ $\xrightarrow[2. NH_3]{1. PCl_5} A$ $\xrightarrow[2. H_2/Ni]{1. P_4O_{10}, \text{heat}} B.$
The final product $(B)$ is:
$PhCOOH$ $\xrightarrow[2. NH_3]{1. PCl_5} A$ $\xrightarrow[2. H_2/Ni]{1. P_4O_{10}, \text{heat}} B.$
The final product $(B)$ is:
- Abenzonitrile
- Bbenzylamine
- Caniline
- Dbenzamide
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Similar Questions
Consider the following set of reactions. What are $A$ and $B$ respectively?
$Y \xleftarrow{B} C_6H_5CN \xrightarrow{A} X$
($Y$ reacts with $2,4-DNP$)
($X$ dissolves in dil. $HCl$)
$Y \xleftarrow{B} C_6H_5CN \xrightarrow{A} X$
($Y$ reacts with $2,4-DNP$)
($X$ dissolves in dil. $HCl$)
What is the number of primary amines possible for the compound having molecular formula $C_4H_{11}N$?
Which one of the following reducing agents is likely to be the most effective in bringing about the following change? $RCONH_2 \to RCH_2NH_2$
Medium
View SolutionIdentify the false statement regarding the preparation of amines by the Hofmann bromamide degradation method.
$Cl-CH_2-COONa$ on boiling with aqueous sodium nitrite gives:
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