Consider the following statements:
$P$: $I$ have fever
$Q$: $I$ will take medicine
$R$: $I$ will take rest
The statement "If $I$ have fever,then $I$ will take medicine and $I$ will take rest" is equivalent to:

  • A
    $(\sim P \vee \sim Q) \wedge (\sim P \vee R)$
  • B
    $(\sim P \vee \sim Q) \wedge (\sim P \vee \sim R)$
  • C
    $(P \vee Q) \wedge (\sim P \vee R)$
  • D
    $(P \vee \sim Q) \wedge (P \vee \sim R)$

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The inverse of the statement pattern $(p \vee q) \rightarrow (p \wedge q)$ is

$p$ and $q$ are two logical statements. If $r: p \rightarrow (\sim p \vee q)$ has truth value false,then the truth values of $p$ and $q$ are respectively:

The correct logical equivalences from the following are:
$(I)$ $p \to (q \to r) \equiv (p \land q) \to r$
$(II)$ $(p \to q) \to r \equiv p \to (q \lor r)$
$(III)$ $(p \to q) \to r \equiv (p \to r) \land (\sim q \to r)$
$(IV)$ $p \to (q \to r) \equiv q \to (p \to r)$

If the Boolean expression $(p \wedge q) \circledast (p \otimes q)$ is a tautology,then $\circledast$ and $\otimes$ are respectively given by

Which of the following statements is logically equivalent to $\sim (p \leftrightarrow q)$?

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