Consider the following statements:
Statement $I$: If $A$ is a non-singular matrix, then $A^{-1}$ exists.
Statement $II$: If $A$ and $B$ are symmetric matrices of the same order, then $(AB - BA)$ is a skew-symmetric matrix.
Choose the correct option.
Statement $I$: If $A$ is a non-singular matrix, then $A^{-1}$ exists.
Statement $II$: If $A$ and $B$ are symmetric matrices of the same order, then $(AB - BA)$ is a skew-symmetric matrix.
Choose the correct option.
- AStatement $I$ is true and statement $II$ is false
- BStatement $I$ is false and statement $II$ is false
- CStatement $I$ is true and statement $II$ is true
- DStatement $I$ is false and statement $II$ is true
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If $p, q, r, s$ are in $A.P.$ and $f(x) = \left| \begin{array}{ccc} p + \sin x & q + \sin x & p - r + \sin x \\ q + \sin x & r + \sin x & -1 + \sin x \\ r + \sin x & s + \sin x & s - q + \sin x \end{array} \right|$ such that $\int_{0}^{\pi} f(x) dx = -4$,then the common difference of the $A.P.$ can be:
$A=\begin{bmatrix} 1 & 0 & 1 \\ 0 & 1 & 1 \\ 0 & 1 & 0 \end{bmatrix} \Rightarrow A^2-2A=$
Let $A=[a_{ij}]$ be a matrix of order $3 \times 3$,with $a_{ij}=(\sqrt{2})^{i+j}$. If the sum of all the elements in the third row of $A^2$ is $\alpha+\beta \sqrt{2}$,where $\alpha, \beta \in Z$,then $\alpha+\beta$ is equal to
DifficultJEE MAIN 2025
View SolutionIf $A, B$ are two non-singular matrices of order $3$ and $|B|=k$, where $k$ is a positive integer, then match the items of List-$I$ with the items of List-$II$.
List-$I$ List-$II$ $A$. $|k^{-1} A^{-1}|$ $I$. $BA^k + A^kB$ $B$. $|\text{Adj}(A^{-1})|$ $II$. $\frac{B\text{Adj}(B)}{|B|}$ $C$. $BAB^{-1} = I \Rightarrow BA^kB^{-1} =$ $III$. $\frac{1}{|B|^3|A|}$ $D$. $\text{Adj}(\text{Adj}(A^{-1})) =$ $IV$. $\frac{1}{|A|}(A^{-1})$ $V$. $\frac{1}{|A|^2}$
| List-$I$ | List-$II$ |
| $A$. $|k^{-1} A^{-1}|$ | $I$. $BA^k + A^kB$ |
| $B$. $|\text{Adj}(A^{-1})|$ | $II$. $\frac{B\text{Adj}(B)}{|B|}$ |
| $C$. $BAB^{-1} = I \Rightarrow BA^kB^{-1} =$ | $III$. $\frac{1}{|B|^3|A|}$ |
| $D$. $\text{Adj}(\text{Adj}(A^{-1})) =$ | $IV$. $\frac{1}{|A|}(A^{-1})$ |
| $V$. $\frac{1}{|A|^2}$ |
Let $A = \begin{bmatrix} 4 & -2 \\ \alpha & \beta \end{bmatrix}$. If $A^2 + \gamma A + 18I = O$,then $\operatorname{det}(A)$ is equal to
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