Consider the given reaction: RCOOAg xrightarr | vedclass

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(B) The given reaction is the Hunsdiecker reaction,which proceeds via a free radical mechanism. The yield of alkyl halides in this reaction follows th

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$CH_3-CH_2-CH_2-COOH$

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(B) The given reaction is the Hunsdiecker reaction,which proceeds via a free radical mechanism. The yield of alkyl halides in this reaction follows the order: Primary $(1^\circ)$ > Secondary $(2^\circ)$ > Tertiary $(3^\circ)$. $1.$ $CH_3-CH_2-CH_2-COOH$ forms a primary radical $(CH_3-CH_2-CH_2^\bullet)$. $2.$ $CH_3-CH(CH_3)-COOH$ forms a secondary radical $((CH_3)_2CH^\bullet)$. $3.$ $CH_3-C(CH_3)_2-COOH$ forms a tertiary radical $((CH_3)_3C^\bullet)$. Therefore,the primary acid $(CH_3-CH_2-CH_2-COOH)$ gives the maximum yield.

Consider the given reaction: $RCOOAg \xrightarrow{Br_2/\Delta} R-Br$. Which one of the following acids will give the maximum yield of $R-Br$ in the above reaction?

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