Consider the straight lines:L_1 : x - y = 1L_ | vedclass

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(D) The slopes of the lines are:$m_1 = 1$ (for $L_1$)$m_2 = -1$ (for $L_2$)$m_3 = -1$ (for $L_3$)$m_4 = 1$ (for $L_4$)$1$. Check perpendicularity:$m_1

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$L_1 \perp L_2, L_1 \perp L_3, L_2$ intersects $L_4$

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(D) The slopes of the lines are:$m_1 = 1$ (for $L_1$)$m_2 = -1$ (for $L_2$)$m_3 = -1$ (for $L_3$)$m_4 = 1$ (for $L_4$)$1$. Check perpendicularity:$m_1 	imes m_2 = 1 	imes (-1) = -1$,so $L_1 \perp L_2$.$m_1 	imes m_3 = 1 	imes (-1) = -1$,so $L_1 \perp L_3$.$2$. Check parallelism:$m_2 = m_3 = -1$,so $L_2 || L_3$.$3$. Check intersection:Since $m_2 
eq m_4$ $(-1 
eq 1)$,$L_2$ and $L_4$ are not parallel and therefore intersect.Comparing with the options,$L_1 \perp L_2$,$L_1 \perp L_3$,and $L_2$ intersects $L_4$ is the correct set of statements.

Consider the straight lines:
$L_1 : x - y = 1$
$L_2 : x + y = 1$
$L_3 : 2x + 2y = 5$
$L_4 : 2x - 2y = 7$
The correct statement is:

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Consider the straight lines:$L_1 : x - y = 1$$L_2 : x + y = 1$$L_3 : 2x + 2y = 5$$L_4 : 2x - 2y = 7$The correct statement is: