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(D) For a charged sphere,the electric field $\overrightarrow{E}$ and electric potential $V$ at a distance $r$ from the center are given by $E = \frac{

Vedclass · Accepted Answer

$|\overrightarrow{E}_1| = |\overrightarrow{E}_2|, V_1 
eq V_2$

Vedclass · Answer

(D) For a charged sphere,the electric field $\overrightarrow{E}$ and electric potential $V$ at a distance $r$ from the center are given by $E = \frac{kq}{r^2}$ and $V = \frac{kq}{r}$.Since both $E$ and $V$ depend only on the distance $r$ from the center of the sphere,if the magnitudes of the electric fields are equal $(|\overrightarrow{E}_1| = |\overrightarrow{E}_2|)$,then the distances of the points from the center must be equal $(r_1 = r_2)$.If $r_1 = r_2$,then the potentials at these points must also be equal $(V_1 = V_2)$.Therefore,it is impossible to have equal magnitudes of electric fields at two points while having different electric potentials at those same points.Thus,option $(d)$ is not possible.

Consider two points $1$ and $2$ in a region outside a charged sphere. These two points are not very far away from the sphere. If $\overrightarrow{E}$ and $V$ represent the electric field vector and the electric potential respectively,which of the following is not possible?

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