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(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N)$,where $V$ is the number of

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$1$,$0$ and $2$ lone pairs of central atom respectively

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(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of monovalent atoms bonded to it.$1$. For $SF_4$: $S$ has $6$ valence electrons. $4$ $F$ atoms are bonded. $	ext{Lone pairs} = \frac{1}{2} (6 - 4) = 1$.$2$. For $CF_4$: $C$ has $4$ valence electrons. $4$ $F$ atoms are bonded. $	ext{Lone pairs} = \frac{1}{2} (4 - 4) = 0$.$3$. For $XeF_4$: $Xe$ has $8$ valence electrons. $4$ $F$ atoms are bonded. $	ext{Lone pairs} = \frac{1}{2} (8 - 4) = 2$.Thus,the number of lone pairs are $1$,$0$,and $2$ respectively.

The correct statement regarding the number of lone pairs on the central atom of molecules $SF_4$,$CF_4$,and $XeF_4$ is:

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