Calculate the Crystal Field Stabilization Ene | vedclass

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Question

(C) For a tetrahedral complex,the $d$-orbitals split into two sets: the lower energy $e$ set and the higher energy $t_2$ set.The energy of the $e$ set

Vedclass · Accepted Answer

$-0.4 \, \Delta_t$

Vedclass · Answer

(C) For a tetrahedral complex,the $d$-orbitals split into two sets: the lower energy $e$ set and the higher energy $t_2$ set.The energy of the $e$ set is $-0.6 \, \Delta_t$ and the energy of the $t_2$ set is $+0.4 \, \Delta_t$.For a high-spin $d^4$ configuration,the electrons fill the orbitals according to Hund's rule: $e^2 t_2^2$.$CFSE = (n_e 	imes -0.6 \, \Delta_t) + (n_{t_2} 	imes +0.4 \, \Delta_t)$$CFSE = (2 	imes -0.6 \, \Delta_t) + (2 	imes +0.4 \, \Delta_t)$$CFSE = -1.2 \, \Delta_t + 0.8 \, \Delta_t = -0.4 \, \Delta_t$

Calculate the Crystal Field Stabilization Energy $(CFSE)$ for a high-spin $d^4$ tetrahedral complex.

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