Decarboxylation of all six possible isomers o | vedclass

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Question

(D) The six isomers of diaminobenzoic acid are decarboxylated to form phenylenediamine isomers.$1$. The three isomers that yield $m$-phenylenediamine

Vedclass · Accepted Answer

$142$

Vedclass · Answer

(D) The six isomers of diaminobenzoic acid are decarboxylated to form phenylenediamine isomers.$1$. The three isomers that yield $m$-phenylenediamine $(A)$ are $2,4$-diaminobenzoic acid,$2,6$-diaminobenzoic acid,and $3,5$-diaminobenzoic acid.$2$. The two isomers that yield $o$-phenylenediamine $(B)$ are $2,3$-diaminobenzoic acid and $3,4$-diaminobenzoic acid.$3$. The one isomer that yields $p$-phenylenediamine $(C)$ is $2,5$-diaminobenzoic acid.$p$-phenylenediamine $(C)$ has a melting point of $142^{\circ} C$.

Decarboxylation of all six possible isomers of diaminobenzoic acids $C_6H_3(NH_2)_2COOH$ yields three products $A, B$ and $C$. Three acids give product $A$,two acids give product $B$ and one acid gives product $C$. The melting point of product $C$ is .....$^{\circ} C$.

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