Define $\Lambda _m = \frac{\kappa \times 1000}{C}$ where $C$ is concentration in $mol \ L^{-1}$ and $\kappa$ is conductivity in $S \ cm^{-1}$.

The conductance of a $0.0015 \ M$ aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized $Pt$ electrodes. The distance between the electrodes is $120 \ cm$ with an area of cross section of $1 \ cm^2$. The conductance of this solution was found to be $5 \times 10^{-7} \ S$. The $pH$ of the solution is $4$. The value of limiting molar conductivity $\left(\Lambda_{m}^0\right)$ of this weak monobasic acid in aqueous solution is $Z \times 10^2 \ S \ cm^{2} \ mol^{-1}$. The value of $Z$ is

Resistance of a conductivity cell at $298 \ K$ for $0.0100 \ M \ KCl$ is $161.8 \ \Omega$. Resistance becomes $190 \ \Omega$ when $0.005 \ M \ NaOH$ solution is filled in this cell. Calculate: $(i)$ cell constant,$(ii)$ specific conductivity for $NaOH$ solution,and $(iii)$ molar conductivity.

The property which decreases with dilution is:

What must be the molarity of $BaCl_2$ solution to have molar conductivity $240 \text{ }\Omega^{-1}\text{cm}^2\text{mol}^{-1}$ and conductivity $0.012 \text{ }\Omega^{-1}\text{cm}^{-1}$ at $25 \text{ }^\circ\text{C}$ (in M)?

The equivalent conductance at infinite dilution of a weak acid such as $HF$: