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(A) The given differential equation is $y'' + (y')^2 + 2y = 0$. The order of a differential equation is the order of the highest derivative present in

Vedclass · Accepted Answer

Order $2$,Degree $1$

Vedclass · Answer

(A) The given differential equation is $y'' + (y')^2 + 2y = 0$. The order of a differential equation is the order of the highest derivative present in the equation. Here,the highest derivative is $y''$,so the order is $2$. The degree of a differential equation is the power of the highest order derivative when the equation is expressed as a polynomial in its derivatives. Here,the highest order derivative $y''$ has an exponent of $1$. Thus,the order is $2$ and the degree is $1$.

Determine the order and degree (if defined) of the differential equation $y'' + (y')^2 + 2y = 0$.

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