Dichromate ion is treated with base,the oxidation number of $Cr$ in the product formed is .... .

  • A
    $3$
  • B
    $4$
  • C
    $5$
  • D
    $6$

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$A$ compound contains atoms $X$,$Y$,and $Z$. The oxidation number of $X$ is $+2$,$Y$ is $+5$ and $Z$ is $-2$. Therefore,a possible formula of the compound is

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Oxidation number of oxygen in ozone $(O_3)$ is

The oxidation number of $C$ in $C_6H_{12}O_6$ is:

Match the Column-$I$ with Column-$II$ for the oxidation states of the central atoms.
Column-$I$ Column-$II$
$A$. $Cr_2O_7^{2-}$ $1$. $+3$
$B$. $MnO_4^{-}$ $2$. $+4$
$C$. $VO_3^{-}$ $3$. $+5$
$D$. $FeF_6^{3-}$ $4$. $+6$
$5$. $+7$

What is the oxidation state of $Cr$ in potassium dichromate?

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