Differentiate the function with respect to $x$: $\sin^{3} x + \cos^{6} x$

(N/A) Let $y = \sin^{3} x + \cos^{6} x$.
Applying the chain rule,we differentiate with respect to $x$:
$\frac{dy}{dx} = \frac{d}{dx}(\sin^{3} x) + \frac{d}{dx}(\cos^{6} x)$.
Using the power rule and chain rule:
$\frac{dy}{dx} = 3 \sin^{2} x \cdot \frac{d}{dx}(\sin x) + 6 \cos^{5} x \cdot \frac{d}{dx}(\cos x)$.
Substituting the derivatives of $\sin x$ and $\cos x$:
$\frac{dy}{dx} = 3 \sin^{2} x \cdot \cos x + 6 \cos^{5} x \cdot (-\sin x)$.
Factoring out $3 \sin x \cos x$:
$\frac{dy}{dx} = 3 \sin x \cos x (\sin x - 2 \cos^{4} x)$.