Find the derivative of f(x) = frac{x+1}{x}. | vedclass

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(B) Given the function $f(x) = \frac{x+1}{x}$.We can simplify the function as $f(x) = \frac{x}{x} + \frac{1}{x} = 1 + x^{-1}$.Now,differentiate with r

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$-\frac{1}{x^2}$

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(B) Given the function $f(x) = \frac{x+1}{x}$.We can simplify the function as $f(x) = \frac{x}{x} + \frac{1}{x} = 1 + x^{-1}$.Now,differentiate with respect to $x$:$\frac{d}{dx} f(x) = \frac{d}{dx} (1 + x^{-1})$.Using the power rule $\frac{d}{dx} x^n = nx^{n-1}$:$\frac{d}{dx} (1) + \frac{d}{dx} (x^{-1}) = 0 + (-1)x^{-1-1} = -x^{-2} = -\frac{1}{x^2}$.

Find the derivative of $f(x) = \frac{x+1}{x}$.

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