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(B) The resistance $R$ of a conductor is given by the formula $R = \rho \frac{l}{A}$, where $\rho$ is the resistivity (specific resistance), $l$ is th

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$3 	imes 10^{-3}\, \Omega$

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(B) The resistance $R$ of a conductor is given by the formula $R = ho \frac{l}{A}$, where $ho$ is the resistivity (specific resistance), $l$ is the length, and $A$ is the cross-sectional area.Given dimensions are $1\,cm 	imes 1\,cm 	imes 100\,cm$.For the resistance between the opposite square faces, the length $l$ is the distance between these faces, which is $100\,cm = 1\,m$.The cross-sectional area $A$ is the area of the square face, which is $1\,cm 	imes 1\,cm = 1\,cm^2 = 10^{-4}\,m^2$.The resistivity $ho = 3 	imes 10^{-7}\, \Omega \cdot m$.Substituting these values into the formula:$R = (3 	imes 10^{-7}\, \Omega \cdot m) 	imes \frac{1\,m}{10^{-4}\,m^2}$$R = 3 	imes 10^{-7} 	imes 10^4\, \Omega$$R = 3 	imes 10^{-3}\, \Omega$.

Dimensions of a block are $1\,cm \times 1\,cm \times 100\,cm$. If the specific resistance of its material is $3 \times 10^{-7}\, \Omega \cdot m$, then the resistance between the opposite rectangular faces (the square ends) is:

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