Dividing x^{3} + 125 by (x - 5),the remainder | vedclass

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(A) To find the remainder when $p(x) = x^{3} + 125$ is divided by $(x - 5)$,we use the Remainder Theorem.According to the Remainder Theorem,if a polyn

Vedclass · Accepted Answer

$250$

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(A) To find the remainder when $p(x) = x^{3} + 125$ is divided by $(x - 5)$,we use the Remainder Theorem.According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$a = 5$.So,the remainder is $p(5) = (5)^{3} + 125$.$p(5) = 125 + 125 = 250$.Therefore,the remainder is $250$.

Dividing $x^{3} + 125$ by $(x - 5)$,the remainder is $\ldots \ldots \ldots .$

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