Divya deposited Rs. 1000 at compound interest | vedclass

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(B) The formula for the amount $A$ under compound interest is $A = P(1 + r/100)^n$,where $P = 1000$,$r = 10$,and $n$ is the number of years.Amount at

Vedclass · Accepted Answer

No,it does not form an $AP$.

Vedclass · Answer

(B) The formula for the amount $A$ under compound interest is $A = P(1 + r/100)^n$,where $P = 1000$,$r = 10$,and $n$ is the number of years.Amount at the end of the $1^{st}$ year: $A_1 = 1000(1 + 10/100)^1 = 1000(1.1) = 1100$.Amount at the end of the $2^{nd}$ year: $A_2 = 1000(1 + 10/100)^2 = 1000(1.21) = 1210$.Amount at the end of the $3^{rd}$ year: $A_3 = 1000(1 + 10/100)^3 = 1000(1.331) = 1331$.The sequence of amounts is $1100, 1210, 1331, \ldots$.To check if it is an $AP$,we calculate the common difference:$A_2 - A_1 = 1210 - 1100 = 110$.$A_3 - A_2 = 1331 - 1210 = 121$.Since $A_2 - A_1 
eq A_3 - A_2$,the difference between consecutive terms is not constant.Therefore,the sequence does not form an $AP$.

Part $I$	Part $II$
$1$. Sixth term of the $A.P.$ $1, 3, 5, 7, \ldots$	$a$. $105$
$2$. Eleventh term of the $A.P.$ $3, 6, 9, 12, \ldots$	$b$. $11$
$3$. Sixteenth term of the $A.P.$ $4, 6, 8, 10, \ldots$	$c$. $33$
$4$. Twenty-first term of the $A.P.$ $5, 10, 15, 20, \ldots$	$d$. $34$

Divya deposited $Rs. 1000$ at compound interest at the rate of $10\%$ per annum. The amounts at the end of the first year,second year,third year,$\ldots,$ form an $AP$. Justify your answer.

Similar Questions

For a given $A.P.$,$T_{7} = 12$ and $T_{12} = 72$. Then,$d = \dots \dots \dots \dots$

Verify that each of the following is an $AP$,and then write its next three terms.
$5, \frac{14}{3}, \frac{13}{3}, 4, \ldots$

Which term of the $AP: 21, 42, 63, 84, \ldots$ is $210$?

Find the sum:
$1+(-2)+(-5)+(-8)+\ldots+(-236)$

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